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13202220131 is a prime number
BaseRepresentation
bin11000100101110100…
…11110010001100011
31021002002022021022222
430102322132101203
5204014232021011
610022013221255
7645110006462
oct142272362143
937062267288
1013202220131
115665344431
12268549182b
131325255699
148d35689d9
15524098ddb
hex312e9e463

13202220131 has 2 divisors, whose sum is σ = 13202220132. Its totient is φ = 13202220130.

The previous prime is 13202220127. The next prime is 13202220193. The reversal of 13202220131 is 13102220231.

13202220131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13202220131 - 22 = 13202220127 is a prime.

It is a super-2 number, since 2×132022201312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (13202220331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601110065 + 6601110066.

It is an arithmetic number, because the mean of its divisors is an integer number (6601110066).

Almost surely, 213202220131 is an apocalyptic number.

13202220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202220131 is an equidigital number, since it uses as much as digits as its factorization.

13202220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13202220131 its reverse (13102220231), we get a palindrome (26304440362).

The spelling of 13202220131 in words is "thirteen billion, two hundred two million, two hundred twenty thousand, one hundred thirty-one".