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132022220220223 = 461286382256443
BaseRepresentation
bin11110000001001011010001…
…100010011110011100111111
3122022110012102112010021120021
4132001023101202132130333
5114301023001334021343
61144442100511233011
736544201456026634
oct3601132142363477
9568405375107507
10132022220220223
1139080344558383
121298295a518767
135888846485258
142485ca3b5618b
15103e3031a50ed
hex7812d189e73f

132022220220223 has 4 divisors (see below), whose sum is σ = 132308602477128. Its totient is φ = 131735837963320.

The previous prime is 132022220220197. The next prime is 132022220220229. The reversal of 132022220220223 is 322022022220231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132022220220223 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132022220220229) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143191127761 + ... + 143191128682.

It is an arithmetic number, because the mean of its divisors is an integer number (33077150619282).

Almost surely, 2132022220220223 is an apocalyptic number.

132022220220223 is a deficient number, since it is larger than the sum of its proper divisors (286382256905).

132022220220223 is an equidigital number, since it uses as much as digits as its factorization.

132022220220223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 286382256904.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 132022220220223 its reverse (322022022220231), we get a palindrome (454044242440454).

The spelling of 132022220220223 in words is "one hundred thirty-two trillion, twenty-two billion, two hundred twenty million, two hundred twenty thousand, two hundred twenty-three".

Divisors: 1 461 286382256443 132022220220223