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132023110211303 = 1311007810001613
BaseRepresentation
bin11110000001001100000110…
…100101100001011011100111
3122022110021201112210111210212
4132001030012211201123213
5114301031312203230203
61144442325103010035
736544232513601053
oct3601140645413347
9568407645714725
10132023110211303
11390807609738a3
1212982b6859991b
135888958985cac
142485d4a028c63
15103e3563a61d8
hex7813069616e7

132023110211303 has 4 divisors (see below), whose sum is σ = 133030920213048. Its totient is φ = 131015300209560.

The previous prime is 132023110211269. The next prime is 132023110211339. The reversal of 132023110211303 is 303112011320231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132023110211303 - 244 = 114430924166887 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132023110261303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503905000676 + ... + 503905000937.

It is an arithmetic number, because the mean of its divisors is an integer number (33257730053262).

Almost surely, 2132023110211303 is an apocalyptic number.

132023110211303 is a deficient number, since it is larger than the sum of its proper divisors (1007810001745).

132023110211303 is a wasteful number, since it uses less digits than its factorization.

132023110211303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1007810001744.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 132023110211303 its reverse (303112011320231), we get a palindrome (435135121531534).

The spelling of 132023110211303 in words is "one hundred thirty-two trillion, twenty-three billion, one hundred ten million, two hundred eleven thousand, three hundred three".

Divisors: 1 131 1007810001613 132023110211303