Base | Representation |
---|---|
bin | 1100000000011110011110… |
… | …1000000001111111111111 |
3 | 1201202010111102021102111100 |
4 | 3000013213220001333333 |
5 | 3212301323024001310 |
6 | 44025021243424143 |
7 | 2531556544631256 |
oct | 300074750017777 |
9 | 51663442242440 |
10 | 13202320531455 |
11 | 4230088835590 |
12 | 1592846525053 |
13 | 749c8698aa13 |
14 | 338dd239b79d |
15 | 17d6516d5ec0 |
hex | c01e7a01fff |
13202320531455 has 48 divisors (see below), whose sum is σ = 24964764757920. Its totient is φ = 6401028480000.
The previous prime is 13202320531331. The next prime is 13202320531483. The reversal of 13202320531455 is 55413502320231.
13202320531455 is a `hidden beast` number, since 1 + 32 + 0 + 23 + 20 + 531 + 4 + 55 = 666.
It is not a de Polignac number, because 13202320531455 - 211 = 13202320529407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 41226955 + ... + 41545955.
It is an arithmetic number, because the mean of its divisors is an integer number (520099265790).
Almost surely, 213202320531455 is an apocalyptic number.
13202320531455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13202320531455 is a deficient number, since it is larger than the sum of its proper divisors (11762444226465).
13202320531455 is a wasteful number, since it uses less digits than its factorization.
13202320531455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 402632 (or 402629 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
Adding to 13202320531455 its reverse (55413502320231), we get a palindrome (68615822851686).
The spelling of 13202320531455 in words is "thirteen trillion, two hundred two billion, three hundred twenty million, five hundred thirty-one thousand, four hundred fifty-five".
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