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13202340241913 is a prime number
BaseRepresentation
bin1100000000011110100011…
…0011001110000111111001
31201202010112210100211011022
43000013220303032013321
53212301343100220123
644025023230112225
72531560204313204
oct300075063160771
951663483324138
1013202340241913
114230098978319
12159285104b675
13749c8aa9c404
14338dd4c4c93b
1517d6532cb1c8
hexc01e8cce1f9

13202340241913 has 2 divisors, whose sum is σ = 13202340241914. Its totient is φ = 13202340241912.

The previous prime is 13202340241873. The next prime is 13202340241933. The reversal of 13202340241913 is 31914204320231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12944395100224 + 257945141689 = 3597832^2 + 507883^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202340241913 - 218 = 13202339979769 is a prime.

It is a super-2 number, since 2×132023402419132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13202340241933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601170120956 + 6601170120957.

It is an arithmetic number, because the mean of its divisors is an integer number (6601170120957).

Almost surely, 213202340241913 is an apocalyptic number.

It is an amenable number.

13202340241913 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202340241913 is an equidigital number, since it uses as much as digits as its factorization.

13202340241913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 13202340241913 in words is "thirteen trillion, two hundred two billion, three hundred forty million, two hundred forty-one thousand, nine hundred thirteen".