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13202410444417 is a prime number
BaseRepresentation
bin1100000000011110110011…
…1111000001011010000001
31201202010201200110110220001
43000013230333001122001
53212302014033210132
644025034214520001
72531562016112215
oct300075477013201
951663650413801
1013202410444417
114230124567517
121592870666001
13749c9c4ac15c
143390002c4945
1517d659546ce7
hexc01ecfc1681

13202410444417 has 2 divisors, whose sum is σ = 13202410444418. Its totient is φ = 13202410444416.

The previous prime is 13202410444387. The next prime is 13202410444439. The reversal of 13202410444417 is 71444401420231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13200025977856 + 2384466561 = 3633184^2 + 48831^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202410444417 - 215 = 13202410411649 is a prime.

It is not a weakly prime, because it can be changed into another prime (13202410445417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601205222208 + 6601205222209.

It is an arithmetic number, because the mean of its divisors is an integer number (6601205222209).

Almost surely, 213202410444417 is an apocalyptic number.

It is an amenable number.

13202410444417 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202410444417 is an equidigital number, since it uses as much as digits as its factorization.

13202410444417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 37.

Adding to 13202410444417 its reverse (71444401420231), we get a palindrome (84646811864648).

The spelling of 13202410444417 in words is "thirteen trillion, two hundred two billion, four hundred ten million, four hundred forty-four thousand, four hundred seventeen".