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132024115225633 is a prime number
BaseRepresentation
bin11110000001001101000010…
…011111010110010000100001
3122022110101022120220112021211
4132001031002133112100201
5114301040341444210013
61144443012523550121
736544266436225021
oct3601150237262041
9568411276815254
10132024115225633
1139081127201a54
12129831a908b341
135888a88c5a627
1424860036bda81
15103e3b472823d
hex7813427d6421

132024115225633 has 2 divisors, whose sum is σ = 132024115225634. Its totient is φ = 132024115225632.

The previous prime is 132024115225621. The next prime is 132024115225643. The reversal of 132024115225633 is 336522511420231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127508179970304 + 4515935255329 = 11291952^2 + 2125073^2 .

It is a cyclic number.

It is not a de Polignac number, because 132024115225633 - 25 = 132024115225601 is a prime.

It is a super-2 number, since 2×1320241152256332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132024115225643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66012057612816 + 66012057612817.

It is an arithmetic number, because the mean of its divisors is an integer number (66012057612817).

Almost surely, 2132024115225633 is an apocalyptic number.

It is an amenable number.

132024115225633 is a deficient number, since it is larger than the sum of its proper divisors (1).

132024115225633 is an equidigital number, since it uses as much as digits as its factorization.

132024115225633 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 132024115225633 its reverse (336522511420231), we get a palindrome (468546626645864).

The spelling of 132024115225633 in words is "one hundred thirty-two trillion, twenty-four billion, one hundred fifteen million, two hundred twenty-five thousand, six hundred thirty-three".