Base | Representation |
---|---|
bin | 10011001101100100100… |
… | …111110100111110111111 |
3 | 11200012210000100121022112 |
4 | 103031210213310332333 |
5 | 133112324214401421 |
6 | 2450302240004235 |
7 | 164245566243164 |
oct | 23154447647677 |
9 | 4605700317275 |
10 | 1320243122111 |
11 | 469a03907481 |
12 | 193a5690067b |
13 | 97662c76cc4 |
14 | 47c85c7a06b |
15 | 245211b745b |
hex | 133649f4fbf |
1320243122111 has 4 divisors (see below), whose sum is σ = 1345153369752. Its totient is φ = 1295332874472.
The previous prime is 1320243122101. The next prime is 1320243122117. The reversal of 1320243122111 is 1112213420231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320243122111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320243122117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12455123741 + ... + 12455123846.
It is an arithmetic number, because the mean of its divisors is an integer number (336288342438).
Almost surely, 21320243122111 is an apocalyptic number.
1320243122111 is a deficient number, since it is larger than the sum of its proper divisors (24910247641).
1320243122111 is an equidigital number, since it uses as much as digits as its factorization.
1320243122111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24910247640.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1320243122111 its reverse (1112213420231), we get a palindrome (2432456542342).
The spelling of 1320243122111 in words is "one trillion, three hundred twenty billion, two hundred forty-three million, one hundred twenty-two thousand, one hundred eleven".
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