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1320243122111 = 5324910247587
BaseRepresentation
bin10011001101100100100…
…111110100111110111111
311200012210000100121022112
4103031210213310332333
5133112324214401421
62450302240004235
7164245566243164
oct23154447647677
94605700317275
101320243122111
11469a03907481
12193a5690067b
1397662c76cc4
1447c85c7a06b
15245211b745b
hex133649f4fbf

1320243122111 has 4 divisors (see below), whose sum is σ = 1345153369752. Its totient is φ = 1295332874472.

The previous prime is 1320243122101. The next prime is 1320243122117. The reversal of 1320243122111 is 1112213420231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1320243122111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320243122117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12455123741 + ... + 12455123846.

It is an arithmetic number, because the mean of its divisors is an integer number (336288342438).

Almost surely, 21320243122111 is an apocalyptic number.

1320243122111 is a deficient number, since it is larger than the sum of its proper divisors (24910247641).

1320243122111 is an equidigital number, since it uses as much as digits as its factorization.

1320243122111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24910247640.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1320243122111 its reverse (1112213420231), we get a palindrome (2432456542342).

The spelling of 1320243122111 in words is "one trillion, three hundred twenty billion, two hundred forty-three million, one hundred twenty-two thousand, one hundred eleven".

Divisors: 1 53 24910247587 1320243122111