Base | Representation |
---|---|
bin | 111101011110110011… |
… | …0111111010000110111 |
3 | 110121210101222200222011 |
4 | 1322331212333100313 |
5 | 4130344203231203 |
6 | 140353115545051 |
7 | 12352554421225 |
oct | 1727546772067 |
9 | 417711880864 |
10 | 132030133303 |
11 | 50aa2628352 |
12 | 2170875b187 |
13 | c5b166c743 |
14 | 6566d69b15 |
15 | 367b1c976d |
hex | 1ebd9bf437 |
132030133303 has 4 divisors (see below), whose sum is σ = 133037997048. Its totient is φ = 131022269560.
The previous prime is 132030133247. The next prime is 132030133309. The reversal of 132030133303 is 303331030231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132030133303 - 225 = 131996578871 is a prime.
It is a super-2 number, since 2×1320301333032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132030133309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503931676 + ... + 503931937.
It is an arithmetic number, because the mean of its divisors is an integer number (33259499262).
Almost surely, 2132030133303 is an apocalyptic number.
132030133303 is a deficient number, since it is larger than the sum of its proper divisors (1007863745).
132030133303 is a wasteful number, since it uses less digits than its factorization.
132030133303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1007863744.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 132030133303 its reverse (303331030231), we get a palindrome (435361163534).
The spelling of 132030133303 in words is "one hundred thirty-two billion, thirty million, one hundred thirty-three thousand, three hundred three".
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