Base | Representation |
---|---|
bin | 1100000000100001011001… |
… | …0010000110011010001011 |
3 | 1201202012111222012202211211 |
4 | 3000020112102012122023 |
5 | 3212304423421431444 |
6 | 44025231045233551 |
7 | 2531615131304653 |
oct | 300102622063213 |
9 | 51665458182754 |
10 | 13203103311499 |
11 | 423044a684842 |
12 | 1592a247028b7 |
13 | 74a07cbc198a |
14 | 339068323363 |
15 | 17d69a2aac34 |
hex | c021648668b |
13203103311499 has 2 divisors, whose sum is σ = 13203103311500. Its totient is φ = 13203103311498.
The previous prime is 13203103311389. The next prime is 13203103311533. The reversal of 13203103311499 is 99411330130231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13203103311499 - 233 = 13194513376907 is a prime.
It is not a weakly prime, because it can be changed into another prime (13203103311799) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601551655749 + 6601551655750.
It is an arithmetic number, because the mean of its divisors is an integer number (6601551655750).
Almost surely, 213203103311499 is an apocalyptic number.
13203103311499 is a deficient number, since it is larger than the sum of its proper divisors (1).
13203103311499 is an equidigital number, since it uses as much as digits as its factorization.
13203103311499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 40.
The spelling of 13203103311499 in words is "thirteen trillion, two hundred three billion, one hundred three million, three hundred eleven thousand, four hundred ninety-nine".
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