1320311411113 has 2 divisors, whose sum is σ = 1320311411114. Its totient is φ = 1320311411112.

The previous prime is 1320311411093. The next prime is 1320311411161. The reversal of 1320311411113 is 3111141130231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1164592780569 + 155718630544 = 1079163^2 + 394612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320311411113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1320311411813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660155705556 + 660155705557.

It is an arithmetic number, because the mean of its divisors is an integer number (660155705557).

Almost surely, 2^{1320311411113} is an apocalyptic number.

It is an amenable number.

1320311411113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320311411113 is an equidigital number, since it uses as much as digits as its factorization.

1320311411113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 1320311411113 its reverse (3111141130231), we get a palindrome (4431452541344).

The spelling of 1320311411113 in words is "one trillion, three hundred twenty billion, three hundred eleven million, four hundred eleven thousand, one hundred thirteen".