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1320312113 is a prime number
BaseRepresentation
bin100111010110010…
…0101110100110001
310102000101210201122
41032230211310301
510200444441423
6335002512025
744501316311
oct11654456461
93360353648
101320312113
1161831103a
1230a205615
131806ca493
14c74cb441
157ada38c8
hex4eb25d31

1320312113 has 2 divisors, whose sum is σ = 1320312114. Its totient is φ = 1320312112.

The previous prime is 1320312101. The next prime is 1320312143. The reversal of 1320312113 is 3112130231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1082936464 + 237375649 = 32908^2 + 15407^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320312113 - 210 = 1320311089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1320312091 and 1320312100.

It is not a weakly prime, because it can be changed into another prime (1320312143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660156056 + 660156057.

It is an arithmetic number, because the mean of its divisors is an integer number (660156057).

Almost surely, 21320312113 is an apocalyptic number.

It is an amenable number.

1320312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320312113 is an equidigital number, since it uses as much as digits as its factorization.

1320312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1320312113 is about 36336.0993090893. The cubic root of 1320312113 is about 1097.0477622300.

Adding to 1320312113 its reverse (3112130231), we get a palindrome (4432442344).

The spelling of 1320312113 in words is "one billion, three hundred twenty million, three hundred twelve thousand, one hundred thirteen".