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132032023440353 is a prime number
BaseRepresentation
bin11110000001010100011001…
…110110110010101111100001
3122022111010201201121110110022
4132001110121312302233201
5114301203041000042403
61144450401344243225
736544666424025431
oct3601243166625741
9568433651543408
10132032023440353
11390845151897a3
1212984835610515
13588974947501a
142486553ad42c1
15103e6c8b42d38
hex781519db2be1

132032023440353 has 2 divisors, whose sum is σ = 132032023440354. Its totient is φ = 132032023440352.

The previous prime is 132032023440319. The next prime is 132032023440451. The reversal of 132032023440353 is 353044320230231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113598250429504 + 18433773010849 = 10658248^2 + 4293457^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132032023440353 is a prime.

It is not a weakly prime, because it can be changed into another prime (132032023440313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016011720176 + 66016011720177.

It is an arithmetic number, because the mean of its divisors is an integer number (66016011720177).

Almost surely, 2132032023440353 is an apocalyptic number.

It is an amenable number.

132032023440353 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032023440353 is an equidigital number, since it uses as much as digits as its factorization.

132032023440353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 35.

Adding to 132032023440353 its reverse (353044320230231), we get a palindrome (485076343670584).

The spelling of 132032023440353 in words is "one hundred thirty-two trillion, thirty-two billion, twenty-three million, four hundred forty thousand, three hundred fifty-three".