Base | Representation |
---|---|
bin | 11110000001010100100000… |
… | …011100100011111001101011 |
3 | 122022111011000102122200201110 |
4 | 132001110200130203321223 |
5 | 114301203302301114311 |
6 | 1144450420334121403 |
7 | 36545002235556411 |
oct | 3601244034437153 |
9 | 568434012580643 |
10 | 132032134004331 |
11 | 39084571636090 |
12 | 12984866650263 |
13 | 5889766346cb2 |
14 | 24865646752b1 |
15 | 103e6d36d28a6 |
hex | 781520723e6b |
132032134004331 has 32 divisors (see below), whose sum is σ = 192965347987200. Its totient is φ = 79636755139200.
The previous prime is 132032134004261. The next prime is 132032134004333. The reversal of 132032134004331 is 133400431230231.
It is not a de Polignac number, because 132032134004331 - 27 = 132032134004203 is a prime.
It is a super-2 number, since 2×1320321340043312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132032134004333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 163569081 + ... + 164374293.
It is an arithmetic number, because the mean of its divisors is an integer number (6030167124600).
Almost surely, 2132032134004331 is an apocalyptic number.
132032134004331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132032134004331 is a deficient number, since it is larger than the sum of its proper divisors (60933213982869).
132032134004331 is a wasteful number, since it uses less digits than its factorization.
132032134004331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 828987.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 132032134004331 its reverse (133400431230231), we get a palindrome (265432565234562).
The spelling of 132032134004331 in words is "one hundred thirty-two trillion, thirty-two billion, one hundred thirty-four million, four thousand, three hundred thirty-one".
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