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1320324231034 = 2660162115517
BaseRepresentation
bin10011001101101001011…
…101001110111101111010
311200012222122222100211201
4103031221131032331322
5133113011000343114
62450314254244414
7164250602535304
oct23155135167572
94605878870751
101320324231034
11469a45675846
12193a79ab670a
1397676a05053
1447c92950974
1524528389874
hex1336974ef7a

1320324231034 has 4 divisors (see below), whose sum is σ = 1980486346554. Its totient is φ = 660162115516.

The previous prime is 1320324231013. The next prime is 1320324231041. The reversal of 1320324231034 is 4301324230231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 839153098809 + 481171132225 = 916053^2 + 693665^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1320324230993 and 1320324231011.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330081057757 + ... + 330081057760.

Almost surely, 21320324231034 is an apocalyptic number.

1320324231034 is a deficient number, since it is larger than the sum of its proper divisors (660162115520).

1320324231034 is an equidigital number, since it uses as much as digits as its factorization.

1320324231034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 660162115519.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 1320324231034 its reverse (4301324230231), we get a palindrome (5621648461265).

The spelling of 1320324231034 in words is "one trillion, three hundred twenty billion, three hundred twenty-four million, two hundred thirty-one thousand, thirty-four".

Divisors: 1 2 660162115517 1320324231034