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132032513343434 = 2116001477879247
BaseRepresentation
bin11110000001010100110111…
…000011100111111111001010
3122022111011222212110010010212
4132001110313003213333022
5114301210041403442214
61144450522124441122
736545014523110334
oct3601246703477712
9568434885403125
10132032513343434
113908474677a180
12129849516a91a2
1358897c6b033c2
14248659cbbc454
15103e706b6453e
hex7815370e7fca

132032513343434 has 8 divisors (see below), whose sum is σ = 216053203652928. Its totient is φ = 60014778792460.

The previous prime is 132032513343421. The next prime is 132032513343469. The reversal of 132032513343434 is 434343315230231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 132032513343391 and 132032513343400.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3000738939602 + ... + 3000738939645.

It is an arithmetic number, because the mean of its divisors is an integer number (27006650456616).

Almost surely, 2132032513343434 is an apocalyptic number.

132032513343434 is a deficient number, since it is larger than the sum of its proper divisors (84020690309494).

132032513343434 is a wasteful number, since it uses less digits than its factorization.

132032513343434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6001477879260.

The product of its (nonzero) digits is 933120, while the sum is 41.

Adding to 132032513343434 its reverse (434343315230231), we get a palindrome (566375828573665).

The spelling of 132032513343434 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred thirteen million, three hundred forty-three thousand, four hundred thirty-four".

Divisors: 1 2 11 22 6001477879247 12002955758494 66016256671717 132032513343434