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132032513343469 is a prime number
BaseRepresentation
bin11110000001010100110111…
…000011100111111111101101
3122022111011222212110010012011
4132001110313003213333231
5114301210041403442334
61144450522124441221
736545014523110414
oct3601246703477755
9568434885403164
10132032513343469
113908474677a202
12129849516a9211
1358897c6b0341b
14248659cbbc47b
15103e706b64564
hex7815370e7fed

132032513343469 has 2 divisors, whose sum is σ = 132032513343470. Its totient is φ = 132032513343468.

The previous prime is 132032513343421. The next prime is 132032513343481. The reversal of 132032513343469 is 964343315230231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79346139446025 + 52686373897444 = 8907645^2 + 7258538^2 .

It is a cyclic number.

It is not a de Polignac number, because 132032513343469 - 213 = 132032513335277 is a prime.

It is a super-2 number, since 2×1320325133434692 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032513943469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016256671734 + 66016256671735.

It is an arithmetic number, because the mean of its divisors is an integer number (66016256671735).

Almost surely, 2132032513343469 is an apocalyptic number.

It is an amenable number.

132032513343469 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032513343469 is an equidigital number, since it uses as much as digits as its factorization.

132032513343469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4199040, while the sum is 49.

The spelling of 132032513343469 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred thirteen million, three hundred forty-three thousand, four hundred sixty-nine".