Base | Representation |
---|---|
bin | 11110000001010100110111… |
… | …000100000010000000100001 |
3 | 122022111011222212122112100101 |
4 | 132001110313010002000201 |
5 | 114301210041420400032 |
6 | 1144450522131022401 |
7 | 36545014524033145 |
oct | 3601246704020041 |
9 | 568434885575311 |
10 | 132032513450017 |
11 | 39084746842264 |
12 | 1298495173aa01 |
13 | 58897c6b3ca7b |
14 | 248659cc09225 |
15 | 103e706b85de7 |
hex | 781537102021 |
132032513450017 has 2 divisors, whose sum is σ = 132032513450018. Its totient is φ = 132032513450016.
The previous prime is 132032513449999. The next prime is 132032513450083. The reversal of 132032513450017 is 710054315230231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118217584129681 + 13814929320336 = 10872791^2 + 3716844^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132032513450017 is a prime.
It is not a weakly prime, because it can be changed into another prime (132032513450417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016256725008 + 66016256725009.
It is an arithmetic number, because the mean of its divisors is an integer number (66016256725009).
Almost surely, 2132032513450017 is an apocalyptic number.
It is an amenable number.
132032513450017 is a deficient number, since it is larger than the sum of its proper divisors (1).
132032513450017 is an equidigital number, since it uses as much as digits as its factorization.
132032513450017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 37.
Adding to 132032513450017 its reverse (710054315230231), we get a palindrome (842086828680248).
The spelling of 132032513450017 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred thirteen million, four hundred fifty thousand, seventeen".
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