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132032513450017 is a prime number
BaseRepresentation
bin11110000001010100110111…
…000100000010000000100001
3122022111011222212122112100101
4132001110313010002000201
5114301210041420400032
61144450522131022401
736545014524033145
oct3601246704020041
9568434885575311
10132032513450017
1139084746842264
121298495173aa01
1358897c6b3ca7b
14248659cc09225
15103e706b85de7
hex781537102021

132032513450017 has 2 divisors, whose sum is σ = 132032513450018. Its totient is φ = 132032513450016.

The previous prime is 132032513449999. The next prime is 132032513450083. The reversal of 132032513450017 is 710054315230231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118217584129681 + 13814929320336 = 10872791^2 + 3716844^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132032513450017 is a prime.

It is not a weakly prime, because it can be changed into another prime (132032513450417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016256725008 + 66016256725009.

It is an arithmetic number, because the mean of its divisors is an integer number (66016256725009).

Almost surely, 2132032513450017 is an apocalyptic number.

It is an amenable number.

132032513450017 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032513450017 is an equidigital number, since it uses as much as digits as its factorization.

132032513450017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75600, while the sum is 37.

Adding to 132032513450017 its reverse (710054315230231), we get a palindrome (842086828680248).

The spelling of 132032513450017 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred thirteen million, four hundred fifty thousand, seventeen".