Base | Representation |
---|---|
bin | 11110000001010101010101… |
… | …100001001101000101011100 |
3 | 122022111020022111010012012222 |
4 | 132001111111201031011130 |
5 | 114301212113222222134 |
6 | 1144451044542444512 |
7 | 36545033300123165 |
oct | 3601252541150534 |
9 | 568436274105188 |
10 | 132033024414044 |
11 | 39084989208086 |
12 | 12984a74893738 |
13 | 5889878963450 |
14 | 248660aa1676c |
15 | 103e736967a2e |
hex | 78155584d15c |
132033024414044 has 48 divisors (see below), whose sum is σ = 249178330613856. Its totient is φ = 60853397472000.
The previous prime is 132033024414043. The next prime is 132033024414059. The reversal of 132033024414044 is 440414420330231.
It is a junction number, because it is equal to n+sod(n) for n = 132033024413995 and 132033024414013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132033024414043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 265477334 + ... + 265974210.
It is an arithmetic number, because the mean of its divisors is an integer number (5191215221122).
Almost surely, 2132033024414044 is an apocalyptic number.
It is an amenable number.
132033024414044 is a deficient number, since it is larger than the sum of its proper divisors (117145306199812).
132033024414044 is a wasteful number, since it uses less digits than its factorization.
132033024414044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 504006 (or 504004 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 132033024414044 its reverse (440414420330231), we get a palindrome (572447444744275).
The spelling of 132033024414044 in words is "one hundred thirty-two trillion, thirty-three billion, twenty-four million, four hundred fourteen thousand, forty-four".
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