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132033110113 is a prime number
BaseRepresentation
bin111101011110111001…
…0010110000001100001
3110121210121120221101101
41322331302112001201
54130400434010423
6140353303434401
712352621630042
oct1727562260141
9417717527341
10132033110113
1150aa4280923
1221709755a01
13c5b2172678
1465675028c9
15367b5b67ad
hex1ebdc96061

132033110113 has 2 divisors, whose sum is σ = 132033110114. Its totient is φ = 132033110112.

The previous prime is 132033110087. The next prime is 132033110173. The reversal of 132033110113 is 311011330231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113079530529 + 18953579584 = 336273^2 + 137672^2 .

It is a cyclic number.

It is not a de Polignac number, because 132033110113 - 29 = 132033109601 is a prime.

It is a super-2 number, since 2×1320331101132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132033110173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016555056 + 66016555057.

It is an arithmetic number, because the mean of its divisors is an integer number (66016555057).

Almost surely, 2132033110113 is an apocalyptic number.

It is an amenable number.

132033110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132033110113 is an equidigital number, since it uses as much as digits as its factorization.

132033110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 132033110113 its reverse (311011330231), we get a palindrome (443044440344).

The spelling of 132033110113 in words is "one hundred thirty-two billion, thirty-three million, one hundred ten thousand, one hundred thirteen".