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132033259331 is a prime number
BaseRepresentation
bin111101011110111001…
…0111010011101000011
3110121210121212112001222
41322331302322131003
54130401003244311
6140353310545255
712352623121061
oct1727562723503
9417717775058
10132033259331
1150aa4372a46
122170980822b
13c5b21c556c
146567541031
15367b5e5adb
hex1ebdcba743

132033259331 has 2 divisors, whose sum is σ = 132033259332. Its totient is φ = 132033259330.

The previous prime is 132033259313. The next prime is 132033259361. The reversal of 132033259331 is 133952330231.

Together with previous prime (132033259313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132033259331 - 214 = 132033242947 is a prime.

It is a super-2 number, since 2×1320332593312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132033259291 and 132033259300.

It is not a weakly prime, because it can be changed into another prime (132033259361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016629665 + 66016629666.

It is an arithmetic number, because the mean of its divisors is an integer number (66016629666).

Almost surely, 2132033259331 is an apocalyptic number.

132033259331 is a deficient number, since it is larger than the sum of its proper divisors (1).

132033259331 is an equidigital number, since it uses as much as digits as its factorization.

132033259331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43740, while the sum is 35.

Adding to 132033259331 its reverse (133952330231), we get a palindrome (265985589562).

The spelling of 132033259331 in words is "one hundred thirty-two billion, thirty-three million, two hundred fifty-nine thousand, three hundred thirty-one".