Base | Representation |
---|---|
bin | 11110000001010101110100… |
… | …011101000001101010001001 |
3 | 122022111021122122201001001212 |
4 | 132001111310131001222021 |
5 | 114301214144103143421 |
6 | 1144451212242422505 |
7 | 36545052201414623 |
oct | 3601256435015211 |
9 | 568437578631055 |
10 | 132033543412361 |
11 | 39085125170208 |
12 | 12984b9a661a35 |
13 | 588992c33aa46 |
14 | 2486659915c13 |
15 | 103e7672d4e5b |
hex | 781574741a89 |
132033543412361 has 2 divisors, whose sum is σ = 132033543412362. Its totient is φ = 132033543412360.
The previous prime is 132033543412261. The next prime is 132033543412411. The reversal of 132033543412361 is 163214345330231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128911749152761 + 3121794259600 = 11353931^2 + 1766860^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132033543412361 is a prime.
It is not a weakly prime, because it can be changed into another prime (132033543412061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016771706180 + 66016771706181.
It is an arithmetic number, because the mean of its divisors is an integer number (66016771706181).
Almost surely, 2132033543412361 is an apocalyptic number.
It is an amenable number.
132033543412361 is a deficient number, since it is larger than the sum of its proper divisors (1).
132033543412361 is an equidigital number, since it uses as much as digits as its factorization.
132033543412361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 41.
Adding to 132033543412361 its reverse (163214345330231), we get a palindrome (295247888742592).
The spelling of 132033543412361 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred forty-three million, four hundred twelve thousand, three hundred sixty-one".
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