Base | Representation |
---|---|
bin | 11110000001010101110100… |
… | …011101000001101010110011 |
3 | 122022111021122122201001010102 |
4 | 132001111310131001222303 |
5 | 114301214144103144103 |
6 | 1144451212242423015 |
7 | 36545052201415013 |
oct | 3601256435015263 |
9 | 568437578631112 |
10 | 132033543412403 |
11 | 39085125170246 |
12 | 12984b9a661a6b |
13 | 588992c33aa79 |
14 | 2486659915c43 |
15 | 103e7672d4e88 |
hex | 781574741ab3 |
132033543412403 has 16 divisors (see below), whose sum is σ = 139853108446560. Its totient is φ = 124219861848576.
The previous prime is 132033543412361. The next prime is 132033543412411. The reversal of 132033543412403 is 304214345330231.
It is a cyclic number.
It is not a de Polignac number, because 132033543412403 - 222 = 132033539218099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132033543412003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 620244101 + ... + 620456937.
It is an arithmetic number, because the mean of its divisors is an integer number (8740819277910).
Almost surely, 2132033543412403 is an apocalyptic number.
132033543412403 is a deficient number, since it is larger than the sum of its proper divisors (7819565034157).
132033543412403 is a wasteful number, since it uses less digits than its factorization.
132033543412403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226486.
The product of its (nonzero) digits is 311040, while the sum is 38.
Adding to 132033543412403 its reverse (304214345330231), we get a palindrome (436247888742634).
The spelling of 132033543412403 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred forty-three million, four hundred twelve thousand, four hundred three".
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