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132034014431542 = 266017007215771
BaseRepresentation
bin11110000001010110010000…
…100001110100100100110110
3122022111022212111000021220201
4132001112100201310210312
5114301221130143302132
61144451331110151114
736545066651126446
oct3601262041644466
9568438774007821
10132034014431542
1139085347032963
12129850b035249a
1358899a5ab6a12
1424866a22c6126
15103e7938262e7
hex781590874936

132034014431542 has 4 divisors (see below), whose sum is σ = 198051021647316. Its totient is φ = 66017007215770.

The previous prime is 132034014431533. The next prime is 132034014431549. The reversal of 132034014431542 is 245134410430231.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1320340144315422 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132034014431549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33008503607884 + ... + 33008503607887.

It is an arithmetic number, because the mean of its divisors is an integer number (49512755411829).

Almost surely, 2132034014431542 is an apocalyptic number.

132034014431542 is a deficient number, since it is larger than the sum of its proper divisors (66017007215774).

132034014431542 is an equidigital number, since it uses as much as digits as its factorization.

132034014431542 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66017007215773.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 132034014431542 its reverse (245134410430231), we get a palindrome (377168424861773).

The spelling of 132034014431542 in words is "one hundred thirty-two trillion, thirty-four billion, fourteen million, four hundred thirty-one thousand, five hundred forty-two".

Divisors: 1 2 66017007215771 132034014431542