Base | Representation |
---|---|
bin | 11110000001010110010000… |
… | …100001110100100100110110 |
3 | 122022111022212111000021220201 |
4 | 132001112100201310210312 |
5 | 114301221130143302132 |
6 | 1144451331110151114 |
7 | 36545066651126446 |
oct | 3601262041644466 |
9 | 568438774007821 |
10 | 132034014431542 |
11 | 39085347032963 |
12 | 129850b035249a |
13 | 58899a5ab6a12 |
14 | 24866a22c6126 |
15 | 103e7938262e7 |
hex | 781590874936 |
132034014431542 has 4 divisors (see below), whose sum is σ = 198051021647316. Its totient is φ = 66017007215770.
The previous prime is 132034014431533. The next prime is 132034014431549. The reversal of 132034014431542 is 245134410430231.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1320340144315422 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132034014431549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33008503607884 + ... + 33008503607887.
It is an arithmetic number, because the mean of its divisors is an integer number (49512755411829).
Almost surely, 2132034014431542 is an apocalyptic number.
132034014431542 is a deficient number, since it is larger than the sum of its proper divisors (66017007215774).
132034014431542 is an equidigital number, since it uses as much as digits as its factorization.
132034014431542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66017007215773.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 132034014431542 its reverse (245134410430231), we get a palindrome (377168424861773).
The spelling of 132034014431542 in words is "one hundred thirty-two trillion, thirty-four billion, fourteen million, four hundred thirty-one thousand, five hundred forty-two".
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