Base | Representation |
---|---|
bin | 11110000001010110010001… |
… | …000000011011100001110011 |
3 | 122022111022220001002221121001 |
4 | 132001112101000123201303 |
5 | 114301221134222033121 |
6 | 1144451331554142431 |
7 | 36545100106255606 |
oct | 3601262100334163 |
9 | 568438801087531 |
10 | 132034022455411 |
11 | 3908535061335a |
12 | 129850b2b81a17 |
13 | 58899a7665c7b |
14 | 24866a33b433d |
15 | 103e7943ad991 |
hex | 78159101b873 |
132034022455411 has 2 divisors, whose sum is σ = 132034022455412. Its totient is φ = 132034022455410.
The previous prime is 132034022455253. The next prime is 132034022455417. The reversal of 132034022455411 is 114554220430231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132034022455411 - 221 = 132034020358259 is a prime.
It is not a weakly prime, because it can be changed into another prime (132034022455417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66017011227705 + 66017011227706.
It is an arithmetic number, because the mean of its divisors is an integer number (66017011227706).
Almost surely, 2132034022455411 is an apocalyptic number.
132034022455411 is a deficient number, since it is larger than the sum of its proper divisors (1).
132034022455411 is an equidigital number, since it uses as much as digits as its factorization.
132034022455411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 132034022455411 its reverse (114554220430231), we get a palindrome (246588242885642).
The spelling of 132034022455411 in words is "one hundred thirty-two trillion, thirty-four billion, twenty-two million, four hundred fifty-five thousand, four hundred eleven".
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