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13203424113 = 3112213180797
BaseRepresentation
bin11000100101111110…
…00100001101110001
31021002011120102212220
430102333010031301
5204020034032423
610022055111253
7645123152565
oct142277041561
937064512786
1013203424113
115665a96a60
122685972529
1313255876b9
148d379d6a5
155242359e3
hex312fc4371

13203424113 has 16 divisors (see below), whose sum is σ = 19213765056. Its totient is φ = 7998415040.

The previous prime is 13203424111. The next prime is 13203424177. The reversal of 13203424113 is 31142430231.

It is a happy number.

13203424113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13203424113 - 21 = 13203424111 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13203424111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17370 + ... + 163427.

It is an arithmetic number, because the mean of its divisors is an integer number (1200860316).

Almost surely, 213203424113 is an apocalyptic number.

It is an amenable number.

13203424113 is a deficient number, since it is larger than the sum of its proper divisors (6010340943).

13203424113 is a wasteful number, since it uses less digits than its factorization.

13203424113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183024.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13203424113 its reverse (31142430231), we get a palindrome (44345854344).

The spelling of 13203424113 in words is "thirteen billion, two hundred three million, four hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 3 11 33 2213 6639 24343 73029 180797 542391 1988767 5966301 400103761 1200311283 4401141371 13203424113