Base | Representation |
---|---|
bin | 11110000001010111001101… |
… | …001011101000000101101011 |
3 | 122022111102111101210022112011 |
4 | 132001113031023220011223 |
5 | 114301230221144222103 |
6 | 1144452020100500351 |
7 | 36545134115406535 |
oct | 3601271513500553 |
9 | 568442441708464 |
10 | 132035032023403 |
11 | 39085819481773 |
12 | 129853350aa6b7 |
13 | 5889b08873192 |
14 | 248675b4d2855 |
15 | 103e802d2ed6d |
hex | 7815cd2e816b |
132035032023403 has 2 divisors, whose sum is σ = 132035032023404. Its totient is φ = 132035032023402.
The previous prime is 132035032023361. The next prime is 132035032023443. The reversal of 132035032023403 is 304320230530231.
It is a strong prime.
It is an emirp because it is prime and its reverse (304320230530231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132035032023403 - 29 = 132035032022891 is a prime.
It is not a weakly prime, because it can be changed into another prime (132035032023443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66017516011701 + 66017516011702.
It is an arithmetic number, because the mean of its divisors is an integer number (66017516011702).
Almost surely, 2132035032023403 is an apocalyptic number.
132035032023403 is a deficient number, since it is larger than the sum of its proper divisors (1).
132035032023403 is an equidigital number, since it uses as much as digits as its factorization.
132035032023403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 31.
Adding to 132035032023403 its reverse (304320230530231), we get a palindrome (436355262553634).
The spelling of 132035032023403 in words is "one hundred thirty-two trillion, thirty-five billion, thirty-two million, twenty-three thousand, four hundred three".
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