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132035050503 = 3283290960761
BaseRepresentation
bin111101011110111100…
…1101111110000000111
3110121210202020112002200
41322331321233300013
54130401433104003
6140353413205543
712352644261126
oct1727571576007
9417722215080
10132035050503
1150aa5386754
122170a3308b3
13c5b26a1925
146567889abd
15367b84b6a3
hex1ebde6fc07

132035050503 has 24 divisors (see below), whose sum is σ = 193084622640. Its totient is φ = 86931519360.

The previous prime is 132035050489. The next prime is 132035050513. The reversal of 132035050503 is 305050530231.

It is not a de Polignac number, because 132035050503 - 213 = 132035042311 is a prime.

It is a super-2 number, since 2×1320350505032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132035050513) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2142643 + ... + 2203403.

It is an arithmetic number, because the mean of its divisors is an integer number (8045192610).

Almost surely, 2132035050503 is an apocalyptic number.

132035050503 is a deficient number, since it is larger than the sum of its proper divisors (61049572137).

132035050503 is a wasteful number, since it uses less digits than its factorization.

132035050503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63759 (or 63756 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 27.

Adding to 132035050503 its reverse (305050530231), we get a palindrome (437085580734).

The spelling of 132035050503 in words is "one hundred thirty-two billion, thirty-five million, fifty thousand, five hundred three".

Divisors: 1 3 9 83 249 747 2909 8727 26181 60761 182283 241447 546849 724341 2173023 5043163 15129489 45388467 176753749 530261247 1590783741 14670561167 44011683501 132035050503