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1320401312 = 2541262541
BaseRepresentation
bin100111010110011…
…1011100110100000
310102000120100002022
41032230323212200
510201010320222
6335004441012
744502140336
oct11654734640
93360510068
101320401312
1161837205a
1230a249168
1318072bc69
14c7511b56
157adc0042
hex4eb3b9a0

1320401312 has 12 divisors (see below), whose sum is σ = 2599540146. Its totient is φ = 660200640.

The previous prime is 1320401287. The next prime is 1320401317. The reversal of 1320401312 is 2131040231.

It can be written as a sum of positive squares in only one way, i.e., 1113156496 + 207244816 = 33364^2 + 14396^2 .

It is a super-3 number, since 3×13204013123 (a number of 28 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1320401317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20631239 + ... + 20631302.

Almost surely, 21320401312 is an apocalyptic number.

It is an amenable number.

1320401312 is a deficient number, since it is larger than the sum of its proper divisors (1279138834).

1320401312 is an equidigital number, since it uses as much as digits as its factorization.

1320401312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41262551 (or 41262543 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1320401312 is about 36337.3267040931. The cubic root of 1320401312 is about 1097.0724668330.

Adding to 1320401312 its reverse (2131040231), we get a palindrome (3451441543).

The spelling of 1320401312 in words is "one billion, three hundred twenty million, four hundred one thousand, three hundred twelve".

Divisors: 1 2 4 8 16 32 41262541 82525082 165050164 330100328 660200656 1320401312