132040134113203 has 2 divisors, whose sum is σ = 132040134113204. Its totient is φ = 132040134113202.

The previous prime is 132040134113177. The next prime is 132040134113213. The reversal of 132040134113203 is 302311431040231.

It is a strong prime.

It is an emirp because it is prime and its reverse (302311431040231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132040134113203 is a prime.

It is not a weakly prime, because it can be changed into another prime (132040134113213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66020067056601 + 66020067056602.

It is an arithmetic number, because the mean of its divisors is an integer number (66020067056602).

Almost surely, 2^{132040134113203} is an apocalyptic number.

132040134113203 is a deficient number, since it is larger than the sum of its proper divisors (1).

132040134113203 is an equidigital number, since it uses as much as digits as its factorization.

132040134113203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 132040134113203 its reverse (302311431040231), we get a palindrome (434351565153434).

The spelling of 132040134113203 in words is "one hundred thirty-two trillion, forty billion, one hundred thirty-four million, one hundred thirteen thousand, two hundred three".