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1320401422303 = 4330707009821
BaseRepresentation
bin10011001101101110000…
…011101100011111011111
311200020012001020002100121
4103031232003230133133
5133113140231003203
62450330052535411
7164252530622605
oct23155603543737
94606161202317
101320401422303
11469a851a8787
12193a9b921567
13976899c0b62
1447c9ccc5875
15245300360bd
hex1336e0ec7df

1320401422303 has 4 divisors (see below), whose sum is σ = 1351108432168. Its totient is φ = 1289694412440.

The previous prime is 1320401422271. The next prime is 1320401422387. The reversal of 1320401422303 is 3032241040231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320401422303 - 25 = 1320401422271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320401426303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15353504868 + ... + 15353504953.

It is an arithmetic number, because the mean of its divisors is an integer number (337777108042).

Almost surely, 21320401422303 is an apocalyptic number.

1320401422303 is a deficient number, since it is larger than the sum of its proper divisors (30707009865).

1320401422303 is an equidigital number, since it uses as much as digits as its factorization.

1320401422303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30707009864.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1320401422303 its reverse (3032241040231), we get a palindrome (4352642462534).

The spelling of 1320401422303 in words is "one trillion, three hundred twenty billion, four hundred one million, four hundred twenty-two thousand, three hundred three".

Divisors: 1 43 30707009821 1320401422303