Base | Representation |
---|---|
bin | 11000100110000010… |
… | …11011001011000001 |
3 | 1021002012201212001122 |
4 | 30103001123023001 |
5 | 204020213324213 |
6 | 10022120242025 |
7 | 645131336351 |
oct | 142301331301 |
9 | 37065655048 |
10 | 13204042433 |
11 | 566637956a |
12 | 2686010315 |
13 | 1325742c7a |
14 | 8d38c0b61 |
15 | 524308d08 |
hex | 31305b2c1 |
13204042433 has 2 divisors, whose sum is σ = 13204042434. Its totient is φ = 13204042432.
The previous prime is 13204042421. The next prime is 13204042447. The reversal of 13204042433 is 33424040231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7216842304 + 5987200129 = 84952^2 + 77377^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13204042433 is a prime.
It is not a weakly prime, because it can be changed into another prime (13204032433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602021216 + 6602021217.
It is an arithmetic number, because the mean of its divisors is an integer number (6602021217).
Almost surely, 213204042433 is an apocalyptic number.
It is an amenable number.
13204042433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204042433 is an equidigital number, since it uses as much as digits as its factorization.
13204042433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 13204042433 its reverse (33424040231), we get a palindrome (46628082664).
The spelling of 13204042433 in words is "thirteen billion, two hundred four million, forty-two thousand, four hundred thirty-three".
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