Base | Representation |
---|---|
bin | 11000100110000100… |
… | …01100001101110001 |
3 | 1021002020010001121122 |
4 | 30103002030031301 |
5 | 204020241241223 |
6 | 10022124432025 |
7 | 645133134122 |
oct | 142302141561 |
9 | 37066101548 |
10 | 13204243313 |
11 | 56664a6488 |
12 | 26860a8615 |
13 | 13257b3531 |
14 | 8d3934049 |
15 | 5243485c8 |
hex | 31308c371 |
13204243313 has 2 divisors, whose sum is σ = 13204243314. Its totient is φ = 13204243312.
The previous prime is 13204243291. The next prime is 13204243357. The reversal of 13204243313 is 31334240231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13149896929 + 54346384 = 114673^2 + 7372^2 .
It is a cyclic number.
It is not a de Polignac number, because 13204243313 - 28 = 13204243057 is a prime.
It is a super-3 number, since 3×132042433133 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13204243813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602121656 + 6602121657.
It is an arithmetic number, because the mean of its divisors is an integer number (6602121657).
Almost surely, 213204243313 is an apocalyptic number.
It is an amenable number.
13204243313 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204243313 is an equidigital number, since it uses as much as digits as its factorization.
13204243313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13204243313 its reverse (31334240231), we get a palindrome (44538483544).
The spelling of 13204243313 in words is "thirteen billion, two hundred four million, two hundred forty-three thousand, three hundred thirteen".
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