Base | Representation |
---|---|
bin | 111101011111001100… |
… | …0100000101000101111 |
3 | 110121211022102020120210 |
4 | 1322332120200220233 |
5 | 4130411014140210 |
6 | 140354302113503 |
7 | 12353102650005 |
oct | 1727630405057 |
9 | 417738366523 |
10 | 132043115055 |
11 | 50aa9994775 |
12 | 21710b7b893 |
13 | c5b4266557 |
14 | 6568988a75 |
15 | 367c3e0e20 |
hex | 1ebe620a2f |
132043115055 has 16 divisors (see below), whose sum is σ = 211431405024. Its totient is φ = 70368854400.
The previous prime is 132043115051. The next prime is 132043115059. The reversal of 132043115055 is 550511340231.
It is an interprime number because it is at equal distance from previous prime (132043115051) and next prime (132043115059).
It is not a de Polignac number, because 132043115055 - 22 = 132043115051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132043115051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3363604 + ... + 3402633.
It is an arithmetic number, because the mean of its divisors is an integer number (13214462814).
Almost surely, 2132043115055 is an apocalyptic number.
132043115055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132043115055 is a deficient number, since it is larger than the sum of its proper divisors (79388289969).
132043115055 is a wasteful number, since it uses less digits than its factorization.
132043115055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6767546.
The product of its (nonzero) digits is 9000, while the sum is 30.
Adding to 132043115055 its reverse (550511340231), we get a palindrome (682554455286).
The spelling of 132043115055 in words is "one hundred thirty-two billion, forty-three million, one hundred fifteen thousand, fifty-five".
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