Base | Representation |
---|---|
bin | 10011001101101111111… |
… | …100100111011101101110 |
3 | 11200020021020212112222101 |
4 | 103031233330213131232 |
5 | 133113221334334014 |
6 | 2450333144205314 |
7 | 164253364225201 |
oct | 23155774473556 |
9 | 4606236775871 |
10 | 1320433121134 |
11 | 469aa1089566 |
12 | 193aaa46983a |
13 | 9769343c16a |
14 | 47ca31b7938 |
15 | 24532be8474 |
hex | 1336ff2776e |
1320433121134 has 8 divisors (see below), whose sum is σ = 1991592498168. Its totient is φ = 656568955080.
The previous prime is 1320433121089. The next prime is 1320433121173. The reversal of 1320433121134 is 4311213340231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1823802292 + ... + 1823803015.
It is an arithmetic number, because the mean of its divisors is an integer number (248949062271).
Almost surely, 21320433121134 is an apocalyptic number.
1320433121134 is a deficient number, since it is larger than the sum of its proper divisors (671159377034).
1320433121134 is a wasteful number, since it uses less digits than its factorization.
1320433121134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3647605490.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1320433121134 its reverse (4311213340231), we get a palindrome (5631646461365).
The spelling of 1320433121134 in words is "one trillion, three hundred twenty billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-four".
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