Base | Representation |
---|---|
bin | 1111101111011… |
… | …01010011111011 |
3 | 100012110112100112 |
4 | 13313231103323 |
5 | 232300402102 |
6 | 21034054535 |
7 | 3162233003 |
oct | 767552373 |
9 | 305415315 |
10 | 132044027 |
11 | 685986a5 |
12 | 3827a44b |
13 | 21482c7b |
14 | 13773003 |
15 | b8d4252 |
hex | 7ded4fb |
132044027 has 2 divisors, whose sum is σ = 132044028. Its totient is φ = 132044026.
The previous prime is 132043993. The next prime is 132044051. The reversal of 132044027 is 720440231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132044027 - 212 = 132039931 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 132043993 and 132044011.
It is not a weakly prime, because it can be changed into another prime (132044057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022013 + 66022014.
It is an arithmetic number, because the mean of its divisors is an integer number (66022014).
Almost surely, 2132044027 is an apocalyptic number.
132044027 is a deficient number, since it is larger than the sum of its proper divisors (1).
132044027 is an equidigital number, since it uses as much as digits as its factorization.
132044027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 23.
The square root of 132044027 is about 11491.0411625753. The cubic root of 132044027 is about 509.2209392044.
Adding to 132044027 its reverse (720440231), we get a palindrome (852484258).
The spelling of 132044027 in words is "one hundred thirty-two million, forty-four thousand, twenty-seven".
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