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13204412032051 is a prime number
BaseRepresentation
bin1100000000100110010001…
…0010011110010000110011
31201202022220011210122221101
43000021210102132100303
53212320113440011201
644030004555505231
72531662432245532
oct300114422362063
951668804718841
1013204412032051
114230a61398979
12159312aa58217
1374a22b091036
14339150074319
1517d72511ed01
hexc026449e433

13204412032051 has 2 divisors, whose sum is σ = 13204412032052. Its totient is φ = 13204412032050.

The previous prime is 13204412032039. The next prime is 13204412032067. The reversal of 13204412032051 is 15023021440231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13204412032051 - 227 = 13204277814323 is a prime.

It is a super-2 number, since 2×132044120320512 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13204412032151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602206016025 + 6602206016026.

It is an arithmetic number, because the mean of its divisors is an integer number (6602206016026).

Almost surely, 213204412032051 is an apocalyptic number.

13204412032051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13204412032051 is an equidigital number, since it uses as much as digits as its factorization.

13204412032051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 13204412032051 its reverse (15023021440231), we get a palindrome (28227433472282).

The spelling of 13204412032051 in words is "thirteen trillion, two hundred four billion, four hundred twelve million, thirty-two thousand, fifty-one".