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132044231234281 is a prime number
BaseRepresentation
bin11110000001011111110001…
…011111110101001011101001
3122022112022020111201122111011
4132001133301133311023221
5114301403041143444111
61144500140555503521
736545611100410402
oct3601376137651351
9568468214648434
10132044231234281
113908970a166a93
1212987081a57ba1
13588a943692522
142486d911629a9
15103eb9075c021
hex7817f17f52e9

132044231234281 has 2 divisors, whose sum is σ = 132044231234282. Its totient is φ = 132044231234280.

The previous prime is 132044231234141. The next prime is 132044231234297. The reversal of 132044231234281 is 182432132440231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90762128471056 + 41282102763225 = 9526916^2 + 6425115^2 .

It is an emirp because it is prime and its reverse (182432132440231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132044231234281 is a prime.

It is a super-2 number, since 2×1320442312342812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132044231234081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022115617140 + 66022115617141.

It is an arithmetic number, because the mean of its divisors is an integer number (66022115617141).

Almost surely, 2132044231234281 is an apocalyptic number.

It is an amenable number.

132044231234281 is a deficient number, since it is larger than the sum of its proper divisors (1).

132044231234281 is an equidigital number, since it uses as much as digits as its factorization.

132044231234281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 221184, while the sum is 40.

The spelling of 132044231234281 in words is "one hundred thirty-two trillion, forty-four billion, two hundred thirty-one million, two hundred thirty-four thousand, two hundred eighty-one".