Base | Representation |
---|---|
bin | 11110000001100000111010… |
… | …001010110010100111101111 |
3 | 122022112102101110220111121220 |
4 | 132001200322022302213233 |
5 | 114301413040304034120 |
6 | 1144500501551554423 |
7 | 36545653233542331 |
oct | 3601407212624757 |
9 | 568472343814556 |
10 | 132045450455535 |
11 | 3908a185400a61 |
12 | 1298736222ba13 |
13 | 588aaa9156816 |
14 | 2487069057451 |
15 | 103ec127e2b40 |
hex | 78183a2b29ef |
132045450455535 has 16 divisors (see below), whose sum is σ = 220458491195904. Its totient is φ = 67362316753952.
The previous prime is 132045450455473. The next prime is 132045450455543. The reversal of 132045450455535 is 535554054540231.
It is a cyclic number.
It is not a de Polignac number, because 132045450455535 - 27 = 132045450455407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 191370217707 + ... + 191370218396.
It is an arithmetic number, because the mean of its divisors is an integer number (13778655699744).
Almost surely, 2132045450455535 is an apocalyptic number.
132045450455535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132045450455535 is a deficient number, since it is larger than the sum of its proper divisors (88413040740369).
132045450455535 is a wasteful number, since it uses less digits than its factorization.
132045450455535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 382740436134.
The product of its (nonzero) digits is 18000000, while the sum is 51.
The spelling of 132045450455535 in words is "one hundred thirty-two trillion, forty-five billion, four hundred fifty million, four hundred fifty-five thousand, five hundred thirty-five".
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