Base | Representation |
---|---|
bin | 11110000001100000111010… |
… | …001101011000000100111011 |
3 | 122022112102101112011221021012 |
4 | 132001200322031120010323 |
5 | 114301413040442230433 |
6 | 1144500502014304135 |
7 | 36545653242364214 |
oct | 3601407215300473 |
9 | 568472345157235 |
10 | 132045451133243 |
11 | 3908a18582414a |
12 | 129873624b804b |
13 | 588aaa933312b |
14 | 248706919240b |
15 | 103ec128c8848 |
hex | 78183a35813b |
132045451133243 has 2 divisors, whose sum is σ = 132045451133244. Its totient is φ = 132045451133242.
The previous prime is 132045451133203. The next prime is 132045451133257. The reversal of 132045451133243 is 342331154540231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132045451133243 - 210 = 132045451132219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132045451133243.
It is not a weakly prime, because it can be changed into another prime (132045451133203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022725566621 + 66022725566622.
It is an arithmetic number, because the mean of its divisors is an integer number (66022725566622).
Almost surely, 2132045451133243 is an apocalyptic number.
132045451133243 is a deficient number, since it is larger than the sum of its proper divisors (1).
132045451133243 is an equidigital number, since it uses as much as digits as its factorization.
132045451133243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 41.
The spelling of 132045451133243 in words is "one hundred thirty-two trillion, forty-five billion, four hundred fifty-one million, one hundred thirty-three thousand, two hundred forty-three".
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