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132045553102433 is a prime number
BaseRepresentation
bin11110000001100001000000…
…010010010110111001100001
3122022112102122122001111200212
4132001201000102112321201
5114301413243043234213
61144500520100023505
736545655621200405
oct3601410022267141
9568472578044625
10132045553102433
113908a228340103
1212987390691b95
13588aac44b6029
142487078937105
15103ec1b81b9a8
hex781840496e61

132045553102433 has 2 divisors, whose sum is σ = 132045553102434. Its totient is φ = 132045553102432.

The previous prime is 132045553102427. The next prime is 132045553102451. The reversal of 132045553102433 is 334201355540231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72524436112384 + 59521116990049 = 8516128^2 + 7714993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132045553102433 is a prime.

It is not a weakly prime, because it can be changed into another prime (132045553102453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022776551216 + 66022776551217.

It is an arithmetic number, because the mean of its divisors is an integer number (66022776551217).

Almost surely, 2132045553102433 is an apocalyptic number.

It is an amenable number.

132045553102433 is a deficient number, since it is larger than the sum of its proper divisors (1).

132045553102433 is an equidigital number, since it uses as much as digits as its factorization.

132045553102433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 41.

The spelling of 132045553102433 in words is "one hundred thirty-two trillion, forty-five billion, five hundred fifty-three million, one hundred two thousand, four hundred thirty-three".