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132049241 is a prime number
BaseRepresentation
bin1111101111011…
…10100101011001
3100012110210111122
413313232211121
5232301033431
621034135025
73162254132
oct767564531
9305423448
10132049241
11685a1605
1238281475
132148545c
1413774c89
15b8d5a7b
hex7dee959

132049241 has 2 divisors, whose sum is σ = 132049242. Its totient is φ = 132049240.

The previous prime is 132049237. The next prime is 132049277. The reversal of 132049241 is 142940231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66504025 + 65545216 = 8155^2 + 8096^2 .

It is a cyclic number.

It is not a de Polignac number, because 132049241 - 22 = 132049237 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132049241.

It is not a weakly prime, because it can be changed into another prime (132049741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66024620 + 66024621.

It is an arithmetic number, because the mean of its divisors is an integer number (66024621).

Almost surely, 2132049241 is an apocalyptic number.

It is an amenable number.

132049241 is a deficient number, since it is larger than the sum of its proper divisors (1).

132049241 is an equidigital number, since it uses as much as digits as its factorization.

132049241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

The square root of 132049241 is about 11491.2680327282. The cubic root of 132049241 is about 509.2276416230.

Adding to 132049241 its reverse (142940231), we get a palindrome (274989472).

The spelling of 132049241 in words is "one hundred thirty-two million, forty-nine thousand, two hundred forty-one".