Base | Representation |
---|---|
bin | 1111101111011… |
… | …10101001100011 |
3 | 100012110210212111 |
4 | 13313232221203 |
5 | 232301041012 |
6 | 21034140151 |
7 | 3162254662 |
oct | 767565143 |
9 | 305423774 |
10 | 132049507 |
11 | 685a1827 |
12 | 38281657 |
13 | 21485605 |
14 | 13774dd9 |
15 | b8d5ba7 |
hex | 7deea63 |
132049507 has 2 divisors, whose sum is σ = 132049508. Its totient is φ = 132049506.
The previous prime is 132049483. The next prime is 132049513. The reversal of 132049507 is 705940231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132049507 - 215 = 132016739 is a prime.
It is not a weakly prime, because it can be changed into another prime (132049607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66024753 + 66024754.
It is an arithmetic number, because the mean of its divisors is an integer number (66024754).
Almost surely, 2132049507 is an apocalyptic number.
132049507 is a deficient number, since it is larger than the sum of its proper divisors (1).
132049507 is an equidigital number, since it uses as much as digits as its factorization.
132049507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
The square root of 132049507 is about 11491.2796067279. The cubic root of 132049507 is about 509.2279835522.
Adding to 132049507 its reverse (705940231), we get a palindrome (837989738).
The spelling of 132049507 in words is "one hundred thirty-two million, forty-nine thousand, five hundred seven".
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