Base | Representation |
---|---|
bin | 11110000001100110011111… |
… | …011000000110001011010011 |
3 | 122022112222212010201010010021 |
4 | 132001212133120012023103 |
5 | 114302012324003101434 |
6 | 1144503332353444311 |
7 | 36546254604033556 |
oct | 3601463730061323 |
9 | 568488763633107 |
10 | 132051443409619 |
11 | 3909178025a078 |
12 | 12988555270697 |
13 | 588b5229264b6 |
14 | 2487476d5069d |
15 | 103ee639d7cb4 |
hex | 78199f6062d3 |
132051443409619 has 2 divisors, whose sum is σ = 132051443409620. Its totient is φ = 132051443409618.
The previous prime is 132051443409559. The next prime is 132051443409643. The reversal of 132051443409619 is 916904344150231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132051443409619 - 27 = 132051443409491 is a prime.
It is a super-2 number, since 2×1320514434096192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132051443409019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66025721704809 + 66025721704810.
It is an arithmetic number, because the mean of its divisors is an integer number (66025721704810).
Almost surely, 2132051443409619 is an apocalyptic number.
132051443409619 is a deficient number, since it is larger than the sum of its proper divisors (1).
132051443409619 is an equidigital number, since it uses as much as digits as its factorization.
132051443409619 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 52.
The spelling of 132051443409619 in words is "one hundred thirty-two trillion, fifty-one billion, four hundred forty-three million, four hundred nine thousand, six hundred nineteen".
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