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132052441505531 is a prime number
BaseRepresentation
bin11110000001100111011010…
…110111100001111011111011
3122022120002102200210122022112
4132001213122313201323323
5114302021400011134111
61144504015410242535
736546321413514311
oct3601473267417373
9568502380718275
10132052441505531
11390921426a2328
121298879358644b
13588b651647ab1
14248752d7240b1
15103eec143ee8b
hex7819dade1efb

132052441505531 has 2 divisors, whose sum is σ = 132052441505532. Its totient is φ = 132052441505530.

The previous prime is 132052441505521. The next prime is 132052441505557. The reversal of 132052441505531 is 135505144250231.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132052441505531 is a prime.

It is a super-2 number, since 2×1320524415055312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132052441505521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026220752765 + 66026220752766.

It is an arithmetic number, because the mean of its divisors is an integer number (66026220752766).

Almost surely, 2132052441505531 is an apocalyptic number.

132052441505531 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052441505531 is an equidigital number, since it uses as much as digits as its factorization.

132052441505531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 132052441505531 its reverse (135505144250231), we get a palindrome (267557585755762).

The spelling of 132052441505531 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, five hundred five thousand, five hundred thirty-one".