Base | Representation |
---|---|
bin | 11110000001100111011010… |
… | …110111111010010011001011 |
3 | 122022120002102200222201012112 |
4 | 132001213122313322103023 |
5 | 114302021400022332243 |
6 | 1144504015412332535 |
7 | 36546321414411251 |
oct | 3601473267722313 |
9 | 568502380881175 |
10 | 132052441605323 |
11 | 390921427602a8 |
12 | 1298879361414b |
13 | 588b651681345 |
14 | 248752d74c5d1 |
15 | 103eec145e818 |
hex | 7819dadfa4cb |
132052441605323 has 2 divisors, whose sum is σ = 132052441605324. Its totient is φ = 132052441605322.
The previous prime is 132052441605319. The next prime is 132052441605367. The reversal of 132052441605323 is 323506144250231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132052441605323 - 22 = 132052441605319 is a prime.
It is not a weakly prime, because it can be changed into another prime (132052441608323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026220802661 + 66026220802662.
It is an arithmetic number, because the mean of its divisors is an integer number (66026220802662).
Almost surely, 2132052441605323 is an apocalyptic number.
132052441605323 is a deficient number, since it is larger than the sum of its proper divisors (1).
132052441605323 is an equidigital number, since it uses as much as digits as its factorization.
132052441605323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 132052441605323 its reverse (323506144250231), we get a palindrome (455558585855554).
The spelling of 132052441605323 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, six hundred five thousand, three hundred twenty-three".
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