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132052510311209 is a prime number
BaseRepresentation
bin11110000001100111011110…
…111110000000001100101001
3122022120002121111021022221222
4132001213132332000030221
5114302022020114424314
61144504030305111425
736546323210405045
oct3601473676001451
9568502544238858
10132052510311209
1139092178518024
12129887b2628575
13588b662988b07
142487538915025
15103eec74d1c8e
hex7819def80329

132052510311209 has 2 divisors, whose sum is σ = 132052510311210. Its totient is φ = 132052510311208.

The previous prime is 132052510311181. The next prime is 132052510311223. The reversal of 132052510311209 is 902113015250231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73948906416025 + 58103603895184 = 8599355^2 + 7622572^2 .

It is an emirp because it is prime and its reverse (902113015250231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132052510311209 - 216 = 132052510245673 is a prime.

It is not a weakly prime, because it can be changed into another prime (132052510311509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026255155604 + 66026255155605.

It is an arithmetic number, because the mean of its divisors is an integer number (66026255155605).

Almost surely, 2132052510311209 is an apocalyptic number.

It is an amenable number.

132052510311209 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052510311209 is an equidigital number, since it uses as much as digits as its factorization.

132052510311209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 35.

The spelling of 132052510311209 in words is "one hundred thirty-two trillion, fifty-two billion, five hundred ten million, three hundred eleven thousand, two hundred nine".