Base | Representation |
---|---|
bin | 11110000001101000011100… |
… | …101010101110000000000011 |
3 | 122022120012021122001111021201 |
4 | 132001220130222232000003 |
5 | 114302031130113141311 |
6 | 1144504321123402031 |
7 | 36546360650031001 |
oct | 3601503452560003 |
9 | 568505248044251 |
10 | 132053545443331 |
11 | 39092659857116 |
12 | 12988a41223317 |
13 | 588b799276c25 |
14 | 24875d61a9a71 |
15 | 10400383029c1 |
hex | 781a1caae003 |
132053545443331 has 2 divisors, whose sum is σ = 132053545443332. Its totient is φ = 132053545443330.
The previous prime is 132053545443277. The next prime is 132053545443361. The reversal of 132053545443331 is 133344545350231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132053545443331 - 213 = 132053545435139 is a prime.
It is a super-2 number, since 2×1320535454433312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132053545443361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026772721665 + 66026772721666.
It is an arithmetic number, because the mean of its divisors is an integer number (66026772721666).
Almost surely, 2132053545443331 is an apocalyptic number.
132053545443331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132053545443331 is an equidigital number, since it uses as much as digits as its factorization.
132053545443331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888000, while the sum is 46.
The spelling of 132053545443331 in words is "one hundred thirty-two trillion, fifty-three billion, five hundred forty-five million, four hundred forty-three thousand, three hundred thirty-one".
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