Base | Representation |
---|---|
bin | 11110000001101001111010… |
… | …000110011110110011100111 |
3 | 122022120100022212200201211011 |
4 | 132001221322012132303213 |
5 | 114302042332412032330 |
6 | 1144505140441523051 |
7 | 36546444543044344 |
oct | 3601517206366347 |
9 | 568510285621734 |
10 | 132055113002215 |
11 | 39093293690327 |
12 | 129891ba1a3487 |
13 | 588b988c61870 |
14 | 24877044577cb |
15 | 10400cac4482a |
hex | 781a7a19ece7 |
132055113002215 has 16 divisors (see below), whose sum is σ = 170830511748288. Its totient is φ = 97417808534016.
The previous prime is 132055113002213. The next prime is 132055113002221. The reversal of 132055113002215 is 512200311550231.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 132055113002215 - 21 = 132055113002213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132055113002213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1039658667 + ... + 1039785676.
It is an arithmetic number, because the mean of its divisors is an integer number (10676906984268).
Almost surely, 2132055113002215 is an apocalyptic number.
132055113002215 is a deficient number, since it is larger than the sum of its proper divisors (38775398746073).
132055113002215 is a wasteful number, since it uses less digits than its factorization.
132055113002215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2079445338.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 132055113002215 its reverse (512200311550231), we get a palindrome (644255424552446).
The spelling of 132055113002215 in words is "one hundred thirty-two trillion, fifty-five billion, one hundred thirteen million, two thousand, two hundred fifteen".
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