Base | Representation |
---|---|
bin | 111101011111100011… |
… | …1011000111100111111 |
3 | 110121212011112121022220 |
4 | 1322333013120330333 |
5 | 4130422140414401 |
6 | 140355421340423 |
7 | 12353312262603 |
oct | 1727707307477 |
9 | 417764477286 |
10 | 132055404351 |
11 | 51005918912 |
12 | 21715107713 |
13 | c5b697a120 |
14 | 656a467503 |
15 | 367d51c336 |
hex | 1ebf1d8f3f |
132055404351 has 32 divisors (see below), whose sum is σ = 191563915200. Its totient is φ = 80431488000.
The previous prime is 132055404329. The next prime is 132055404391. The reversal of 132055404351 is 153404550231.
It is not a de Polignac number, because 132055404351 - 222 = 132051210047 is a prime.
It is a super-2 number, since 2×1320554043512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132055404311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17489325 + ... + 17496873.
It is an arithmetic number, because the mean of its divisors is an integer number (5986372350).
Almost surely, 2132055404351 is an apocalyptic number.
132055404351 is a deficient number, since it is larger than the sum of its proper divisors (59508510849).
132055404351 is a wasteful number, since it uses less digits than its factorization.
132055404351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12107.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 132055404351 its reverse (153404550231), we get a palindrome (285459954582).
The spelling of 132055404351 in words is "one hundred thirty-two billion, fifty-five million, four hundred four thousand, three hundred fifty-one".
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